Two people are pushing a disabled car. One exerts a force of 200 N east, the other a force of 150 N east. What is the net force exerted on the car? (Assume friction to be negligible.)
It’s for science and my science teacher is really ignorant and doesn’t know how to teach properly. A few kids have already dropped her classes and she hasn’t even given out formulas and expects us to do this. Could anyone help solve this ASAP? Thanks!
sum of forces = 350N east.
if it had been 200 N east and 150 N west, then the sum = 50 N east.
if 200N east and 150 N north, then the sum would have been
sqrt(150^2 + 200^2) north east
draw the forces as vectors, then add them.
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September 25th, 2009 at 7:53 pm
sum of forces = 350N east.
if it had been 200 N east and 150 N west, then the sum = 50 N east.
if 200N east and 150 N north, then the sum would have been
sqrt(150^2 + 200^2) north east
draw the forces as vectors, then add them.
References :
September 25th, 2009 at 8:33 pm
As per the data provided by you I think both of them are pushing the car towards east.
That is the forces applied by them are acting in the same direction.
According to vector addition when to vectors are acting in the same direction the sum of the vectors = sum of their magnitudes
In this case the magnitude of net resultant force is 200+50 = 350N
and this is eastward directed.
References :