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On a frictionless air track, a 0.155kg glider moving at 1.05m/s to the right collides with and sticks to a stationary 0.235kg glider.
What must be the net momentum of this system after the collision?
Why?
Find the speed of the gliders after the collision,Is kinetic energy conserved during the collision?

m1v1 + m2v2 = m1v’1 + m2v’2

Since v2 = 0 then m2v2 = 0 and the velocity of v’1 = v’2 because they stuck together, the formula can be rewritten as:

m1v1 = v’(m1 + m2) to solve for v’ (post-collision velocity):

v’ = (m1v1)/(m1+m2)

In those equations all of your answers can be found.

Three forces are applied to a 10 kg box. The magnitude and direction of the forces are:
1) 5.0N due North
2) 3.0N due West
3) 6.0N @ 30 degrees S of E

Determine the net force acting on the box (include both magnitude and direction). What is the net acceleration of the box?

VECTOR Add East and South Components of 6.0 N force, respectively, to 3N and 5N forces.
ie
East Component of 6N = 6 cos 30° = 5.2 N => added to 3.0 N W = 2.2 N, E
South Component of 6N = 6 sin 30° = 3.0 N => added to 5.0 N N = 2.0 N, N
Size of Fnet = √2.2²+2.0² = √8.84 = 3.0 N ANS
Direction of Fnet = arctan 2/2.2 = 42° ANS

Net Accelertion on box = Fnet/m = 0.3 m/s² at 42° ANS

For most Americans, the house is a major part of their net worth.

How much has the down grading of home prices affected the net worth of average Americans since the "housing bust"?

Of the average American? Not much.

Think of it this way: most people who own homes already had them before the bubble, and now still have them after. Those didn’t lose much if any value. They simply went up and then came back down, but since there was never a sale, none of that added "worth" was ever realized.

A 1 kg ball is thrown straight up in the air. What is the net force acting on the ball when it reaches its maximum height? What is the ball’s acceleration at that point?

There is only one force on the ball, the force of gravity. Since the acceleration of gravity is always 9.8 m/s^2, the acceleration of the ball is 9.8m/s^2 downward. Since we know force is the acceleration times the mass of an object, multiply 9.8m/s^2 by 1 kg, to get the force, 9.8N.

1) Centripetal and centrifugal force on the object is equal and opposite, so both cancel each other and net force is zero.
2) The velocity constantly changes, and change in velocity cannot be zero and change is towards the center , thus acceleration cannot be zero since a=change in velocity/change in time, that means net force is in the direction towards the center( because direction of force is same as direction of acceleration.)
3) If Net force is non zero, why doesn’t object goes to the center?

Tie a ball to a string and whirl it over your head. The only two forces (neglecting air resistance) acting on the ball are gravity and the tension in the string, and if you spin it fast enough, the tension will be much greater than gravity, and we can neglect gravity as well. So one force pointing towards the center of the circle is all that is needed to maintain circular motion. The reason is deceptively simple. When you accelerate at a right angle to your velocity, the magnitude of the velocity is unchanged, only its direction. If you know a little differential calculus, it’s a very easy thing to show:
A particle moving in a circular path of radius R in a circle around the origin with speed u has position given by
s = ( R cos((u/R) t) , R sin((u/R) t)) )
where u/R is the angular frequency of the sinusoids.
we can find the acceleration by taking two derivatives:
v = ( - u sin((u/R) t) , u cos((u/R) t) )
a = ( - u^2/R sin((u/R) t) , - u^2/R cos((u/R) t) )
notice that the magnitude of a is
|a| = u^2/R
and that is points in the direction opposite the position:
a/|a| = - s/|s|

All the company is - is a desk and a computer (for the sake of argument) but brings in Net Revenue of around $50,000 a month on avarage for the last year, so an avarage of 600K per year in NET INCOME. it also owns a few brand names and contracts with high net worth individuals that are worth millions in future income.

How do you calculate the net worth of a company like that?
The company has no liabilities as well, only income and expenses.

Assign an amount as an asset called goodwill

A 3kg mass is observed moving at a constant velocity of 16m/s. What is the net force acting on the mass?

I can find the answer, if someone would just tell me the proper equation for it. Please?

This seems to be asking about Newton’s 1st law - ‘a body will continue moving uniformly in a straight line unless acted upon by an external force’. Your 3kg mass is "moving at a constant velocity of 16m/s", so we can deduce that the net force acting on it is zero.

‘Net force’ means any difference, for example, between friction and a driving force, or between gravitational force and a supporting force.

hey guys
I have a question about net income and gross profit.
How gross income and net income are likely to be affected when a company add a new line beside their traditional line?
thanks
hey guys
I have a question about net income and gross profit.
How gross income and net income are likely to be affected when a company add a new line beside their traditional line? if a cereal company adds a new line that is related to its previous line ( new cereal and food and grain-based products ) but outside their traditional line, what will happen to their net income and gross profit?
thanks
if a cereal company adds a new line that is related to its previous line ( new cereal and food and grain-based products ) but outside their traditional line, what will happen to their net income and gross profit?
thanks

Not a tax question.

But to answer your question, it could go either way. Merely adding a product line does not assure success of the line or an improvement of net profit. If Microsoft came out with a line of perfumes, it would probably fail miserably. Ditto if Nike tried to get in the router market.

This is for junior high… So far I’ve heard 30 ft but that seems a little far back.
So my question is in junior high volleyball, how far from the net do you have to serve?

…the out of bounds line of the volleyball court….so ya probably like 30ft. All the courts are the same…

When a 100 gram mass is suspended from a vertical spring and it remains motionless, what is the net force on the mass in this equilibrium position?

F = ma

a = 0

F = 0